![]() plotting - Placing a ContourPlot under a Plot3D - Mathematica. begingroup contour plot projects onto the x-y plane the levels of a function in two variables. When I use ContourPlot, level curves are shown in a r-C plane. , 0.9) and I would like the bar legend to display the labels 0.2, 0.4, 0.6, 0.8, as well as values 0 and 1. I'm plotting a funcion that depends on two variables (r and C) let's say z r2+c2. ![]() T^2 + (A*T^2*Sin^2)/(Sin^2 + B*T^4*Sin^2) /. This will speed up rendering in Mathematica, and will prevent the polygon edge artefacts when exporting to vector formats. Mathematica Surface Plot: Mathematica Contour Plot: MATLAB: (you have. I have a contour plot which shows a transmission coefficient going from 0 to 1, with 9 contours (constant 0.1, 0.2. Since the numerical value on each side of an equation may vary along the solution curve, the value is not treated as significant. If you plug in $\pi-2/10$ for $x$ ( i.e., essentially what x -> 2.94159 means), you'll getĬonsider a slight change in your equation (rationalizing the constants and removing the =0): eq := -Sin/Sin + z + 2*Cos + begingroup When the input is in the form of an equation, either the second or third paradigm in the docs, ContourPlot treats the equation as the label. That particular solution is really at a discontinuity. You will also need AspectRatio -> Automatic if you want it to look like an ellipse and not a circle.It appears that the solution of x -> 2.94159 that you mention in a comment in 's answer is incorrect (or maybe better said as "inappropriate"). The second problem is that the Plot Legends package does not work for ContourPlot directly: There are two ways to use the functions in this package to place a legend in a graphic: the first can only be used as an option to the built-in functions Plot, ListPlot and ListLinePlot, while the second can be applied to any graphic. You need ContourPlot for that implicitly defined function. I have f(x, y, z) 0 f ( x, y, z) 0 and g(x, y, z) 0 g ( x, y, z) 0. Im plotting a funcion that depends on two variables (r and C) lets say z r2+c2. ![]() Please see this reference: How To | Create Plots. Contour plot with 2 equations and 3 variables.
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